Re: [PATCH] sched: Combine ENQUEUE_MIGRATED check in activate_task()

From: Zhongqiu Han
Date: Mon Jul 28 2025 - 05:52:42 EST


On 7/25/2025 3:14 PM, K Prateek Nayak wrote:
Hello Zhongqiu,

On 7/24/2025 5:42 PM, Zhongqiu Han wrote:
Combine the task_on_rq_migrating() check and the sched_mm_cid_migrate_to()
invocation into a single conditional block. This removes a redundant flag
check and slightly reduces the instruction count in a hot path.

Signed-off-by: Zhongqiu Han <quic_zhonhan@xxxxxxxxxxx>
---
- This is a slight optimization and code cleanup, please let me know if you'd prefer to keep the current structure.
- Thanks

kernel/sched/core.c | 4 ++--
1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/kernel/sched/core.c b/kernel/sched/core.c
index 2343f5691c54..d6063cf503ee 100644
--- a/kernel/sched/core.c
+++ b/kernel/sched/core.c
@@ -2118,10 +2118,10 @@ inline bool dequeue_task(struct rq *rq, struct task_struct *p, int flags)
void activate_task(struct rq *rq, struct task_struct *p, int flags)
{
- if (task_on_rq_migrating(p))
+ if (task_on_rq_migrating(p)) {
flags |= ENQUEUE_MIGRATED;
- if (flags & ENQUEUE_MIGRATED)

I think "ENQUEUE_MIGRATED" can be individually set without
task_on_rq_migrating() in the wakeup path via ttwu_do_activate().

In that case "p->on_rq", goes from "0" to "TASK_ON_RQ_QUEUED" directly
without going through an intermediate "TASK_ON_RQ_MIGRATING" but
"ENQUEUE_MIGRATED" will be set if "p->task_cpu" was changed during
wakeup.

Hi Prateek

You're right. Thanks for the nice review~



--
Thx and BRs,
Zhongqiu Han