Re: [PATCH] sched: Combine ENQUEUE_MIGRATED check in activate_task()

From: K Prateek Nayak
Date: Fri Jul 25 2025 - 03:15:03 EST


Hello Zhongqiu,

On 7/24/2025 5:42 PM, Zhongqiu Han wrote:
> Combine the task_on_rq_migrating() check and the sched_mm_cid_migrate_to()
> invocation into a single conditional block. This removes a redundant flag
> check and slightly reduces the instruction count in a hot path.
>
> Signed-off-by: Zhongqiu Han <quic_zhonhan@xxxxxxxxxxx>
> ---
> - This is a slight optimization and code cleanup, please let me know if you'd prefer to keep the current structure.
> - Thanks
>
> kernel/sched/core.c | 4 ++--
> 1 file changed, 2 insertions(+), 2 deletions(-)
>
> diff --git a/kernel/sched/core.c b/kernel/sched/core.c
> index 2343f5691c54..d6063cf503ee 100644
> --- a/kernel/sched/core.c
> +++ b/kernel/sched/core.c
> @@ -2118,10 +2118,10 @@ inline bool dequeue_task(struct rq *rq, struct task_struct *p, int flags)
>
> void activate_task(struct rq *rq, struct task_struct *p, int flags)
> {
> - if (task_on_rq_migrating(p))
> + if (task_on_rq_migrating(p)) {
> flags |= ENQUEUE_MIGRATED;
> - if (flags & ENQUEUE_MIGRATED)

I think "ENQUEUE_MIGRATED" can be individually set without
task_on_rq_migrating() in the wakeup path via ttwu_do_activate().

In that case "p->on_rq", goes from "0" to "TASK_ON_RQ_QUEUED" directly
without going through an intermediate "TASK_ON_RQ_MIGRATING" but
"ENQUEUE_MIGRATED" will be set if "p->task_cpu" was changed during
wakeup.

--
Thanks and Regards,
Prateek

> sched_mm_cid_migrate_to(rq, p);
> + }
>
> enqueue_task(rq, p, flags);
>