Re: [RESEND PATCH v4] sched: do not call __put_task_struct() on rt if pi_blocked_on is set
From: Luis Claudio R. Goncalves
Date: Tue Jun 17 2025 - 09:22:38 EST
On Tue, Jun 17, 2025 at 11:26:09AM +0200, Peter Zijlstra wrote:
> On Fri, Jun 13, 2025 at 12:05:14PM -0300, Luis Claudio R. Goncalves wrote:
> > With PREEMPT_RT enabled, some of the calls to put_task_struct() coming
> > from rt_mutex_adjust_prio_chain() could happen in preemptible context and
> > with a mutex enqueued. That could lead to this sequence:
> >
> > rt_mutex_adjust_prio_chain()
> > put_task_struct()
> > __put_task_struct()
> > sched_ext_free()
> > spin_lock_irqsave()
> > rtlock_lock() ---> TRIGGERS
> > lockdep_assert(!current->pi_blocked_on);
> >
> > Fix that by unconditionally resorting to the deferred call to
> > __put_task_struct() if PREEMPT_RT is enabled.
> >
>
> Should this have a Fixes: tag and go into /urgent?
Makes sense! I will add the tag:
Fixes: 893cdaaa3977b ("sched: avoid false lockdep splat in put_task_struct()")
and resend.
Thank you!
> > Suggested-by: Crystal Wood <crwood@xxxxxxxxxx>
> > Signed-off-by: Luis Claudio R. Goncalves <lgoncalv@xxxxxxxxxx>
> > ---
> >
> > Resent as a gentle reminder, because this issue results in scary backtraces,
> > not obvious to debug and pinpoint root cause.
> >
> > v2: (Rostedt) remove the #ifdef from put_task_struct() and create
> > tsk_is_pi_blocked_on() in sched.h to make the change cleaner.
> > v3: (Sebastian, PeterZ) always call the deferred __put_task_struct() on RT.
> > v4: Fix the implementation of what was requested on v3.
> >
> > include/linux/sched/task.h | 17 ++++++++---------
> > 1 file changed, 8 insertions(+), 9 deletions(-)
> >
> > diff --git a/include/linux/sched/task.h b/include/linux/sched/task.h
> > index 0f2aeb37bbb04..51678a541477a 100644
> > --- a/include/linux/sched/task.h
> > +++ b/include/linux/sched/task.h
> > @@ -134,11 +134,8 @@ static inline void put_task_struct(struct task_struct *t)
> > if (!refcount_dec_and_test(&t->usage))
> > return;
> >
> > - /*
> > - * In !RT, it is always safe to call __put_task_struct().
> > - * Under RT, we can only call it in preemptible context.
> > - */
> > - if (!IS_ENABLED(CONFIG_PREEMPT_RT) || preemptible()) {
> > + /* In !RT, it is always safe to call __put_task_struct(). */
> > + if (!IS_ENABLED(CONFIG_PREEMPT_RT)) {
> > static DEFINE_WAIT_OVERRIDE_MAP(put_task_map, LD_WAIT_SLEEP);
> >
> > lock_map_acquire_try(&put_task_map);
> > @@ -148,11 +145,13 @@ static inline void put_task_struct(struct task_struct *t)
> > }
> >
> > /*
> > - * under PREEMPT_RT, we can't call put_task_struct
> > + * Under PREEMPT_RT, we can't call __put_task_struct
> > * in atomic context because it will indirectly
> > - * acquire sleeping locks.
> > + * acquire sleeping locks. The same is true if the
> > + * current process has a mutex enqueued (blocked on
> > + * a PI chain).
> > *
> > - * call_rcu() will schedule delayed_put_task_struct_rcu()
> > + * call_rcu() will schedule __put_task_struct_rcu_cb()
> > * to be called in process context.
> > *
> > * __put_task_struct() is called when
> > @@ -165,7 +164,7 @@ static inline void put_task_struct(struct task_struct *t)
> > *
> > * delayed_free_task() also uses ->rcu, but it is only called
> > * when it fails to fork a process. Therefore, there is no
> > - * way it can conflict with put_task_struct().
> > + * way it can conflict with __put_task_struct().
> > */
> > call_rcu(&t->rcu, __put_task_struct_rcu_cb);
> > }
> >
> > ----- End forwarded message -----
> >
>
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