Re: [PATCH 1/1] tty: disassociate_ctty() sends the extra SIGCONT

From: Peter Hurley
Date: Sat Sep 21 2013 - 16:25:21 EST


On 09/21/2013 02:34 PM, Oleg Nesterov wrote:
Peter, sorry for delay, I was sick.

On 09/17, Peter Hurley wrote:

On 09/15/2013 11:50 AM, Oleg Nesterov wrote:

Put the "!on_exit" check back to restore the old behaviour.

Cc: stable@xxxxxxxxxxxxxxx # v3.10+
Signed-off-by: Oleg Nesterov <oleg@xxxxxxxxxx>
Reported-by: Karel Srot <ksrot@xxxxxxxxxx>

Reviewed-by: Peter Hurley <peter@xxxxxxxxxxxxxxxxxx>

Thanks!

Can I ask the question? tty_signal_session_leader() is probably fine,
but it _looks_ buggy or at least confusing to me.

do_each_pid_task(tty->session, PIDTYPE_SID, p) {
spin_lock_irq(&p->sighand->siglock);
if (p->signal->tty == tty) {
p->signal->tty = NULL;
/* We defer the dereferences outside fo
the tasklist lock */
refs++;
}
if (!p->signal->leader) {
spin_unlock_irq(&p->sighand->siglock);
continue;
}
__group_send_sig_info(SIGHUP, SEND_SIG_PRIV, p);
__group_send_sig_info(SIGCONT, SEND_SIG_PRIV, p);
put_pid(p->signal->tty_old_pgrp); /* A noop */
spin_lock(&tty->ctrl_lock);
tty_pgrp = get_pid(tty->pgrp);

I guess this can happen only once, so we could even add WARN_ON(tty_pgrp)
before get_pid(). But this look confusing, as if we can do get_pid()
multiple times and leak tty->pgrp.

if (tty->pgrp)
p->signal->tty_old_pgrp = get_pid(tty->pgrp);

else? We already did put_pid(tty_old_pgrp), we should clear it.

IOW, do you think the patch below makes sense or I missed something?
Just curious.

The code block you're referring to only executes once because there is
only one session leader.

Regards,
Peter Hurley

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