Re: [PATCH 1/4] spi: s3c64xx: modified error interrupt handling and init

From: Tomasz Figa
Date: Fri Feb 08 2013 - 03:33:14 EST


On Thursday 07 of February 2013 09:46:58 Girish KS wrote:
> On Thu, Feb 7, 2013 at 3:09 AM, Tomasz Figa <t.figa@xxxxxxxxxxx> wrote:
> > Hi Girish,
> >
> > On Wednesday 06 of February 2013 12:12:29 Girish KS wrote:
> >> On Wed, Feb 6, 2013 at 2:26 AM, Grant Likely
> >> <grant.likely@xxxxxxxxxxxx>>
> > wrote:
> >> > On Tue, 5 Feb 2013 15:09:41 -0800, Girish K S
> >
> > <girishks2000@xxxxxxxxx> wrote:
> >> >> The status of the interrupt is available in the status register,
> >> >> so reading the clear pending register and writing back the same
> >> >> value will not actually clear the pending interrupts. This patch
> >> >> modifies the interrupt handler to read the status register and
> >> >> clear the corresponding pending bit in the clear pending register.
> >> >>
> >> >> Modified the hwInit function to clear all the pending interrupts.
> >> >>
> >> >> Signed-off-by: Girish K S <ks.giri@xxxxxxxxxxx>
> >> >> ---
> >> >>
> >> >> drivers/spi/spi-s3c64xx.c | 41
> >> >> +++++++++++++++++++++++++---------------- 1 file changed, 25
> >> >> insertions(+), 16 deletions(-)
> >> >>
> >> >> diff --git a/drivers/spi/spi-s3c64xx.c b/drivers/spi/spi-s3c64xx.c
> >> >> index ad93231..b770f88 100644
> >> >> --- a/drivers/spi/spi-s3c64xx.c
> >> >> +++ b/drivers/spi/spi-s3c64xx.c
> >> >> @@ -997,25 +997,30 @@ static irqreturn_t s3c64xx_spi_irq(int irq,
> >> >> void *data)>>
> >> >>
> >> >> {
> >> >>
> >> >> struct s3c64xx_spi_driver_data *sdd = data;
> >> >> struct spi_master *spi = sdd->master;
> >> >>
> >> >> - unsigned int val;
> >> >> + unsigned int val, clr = 0;
> >> >>
> >> >> - val = readl(sdd->regs + S3C64XX_SPI_PENDING_CLR);
> >> >> + val = readl(sdd->regs + S3C64XX_SPI_STATUS);
> >> >>
> >> >> - val &= S3C64XX_SPI_PND_RX_OVERRUN_CLR |
> >> >> - S3C64XX_SPI_PND_RX_UNDERRUN_CLR |
> >> >> - S3C64XX_SPI_PND_TX_OVERRUN_CLR |
> >> >> - S3C64XX_SPI_PND_TX_UNDERRUN_CLR;
> >> >> -
> >> >> - writel(val, sdd->regs + S3C64XX_SPI_PENDING_CLR);
> >> >> -
> >> >> - if (val & S3C64XX_SPI_PND_RX_OVERRUN_CLR)
> >> >> + if (val & S3C64XX_SPI_ST_RX_OVERRUN_ERR) {
> >> >> + clr = S3C64XX_SPI_PND_RX_OVERRUN_CLR;
> >> >>
> >> >> dev_err(&spi->dev, "RX overrun\n");
> >> >>
> >> >> - if (val & S3C64XX_SPI_PND_RX_UNDERRUN_CLR)
> >> >> + }
> >> >> + if (val & S3C64XX_SPI_ST_RX_UNDERRUN_ERR) {
> >> >> + clr |= S3C64XX_SPI_PND_RX_UNDERRUN_CLR;
> >> >>
> >> >> dev_err(&spi->dev, "RX underrun\n");
> >> >>
> >> >> - if (val & S3C64XX_SPI_PND_TX_OVERRUN_CLR)
> >> >> + }
> >> >> + if (val & S3C64XX_SPI_ST_TX_OVERRUN_ERR) {
> >> >> + clr |= S3C64XX_SPI_PND_TX_OVERRUN_CLR;
> >> >>
> >> >> dev_err(&spi->dev, "TX overrun\n");
> >> >>
> >> >> - if (val & S3C64XX_SPI_PND_TX_UNDERRUN_CLR)
> >> >> + }
> >> >> + if (val & S3C64XX_SPI_ST_TX_UNDERRUN_ERR) {
> >> >> + clr |= S3C64XX_SPI_PND_TX_UNDERRUN_CLR;
> >> >>
> >> >> dev_err(&spi->dev, "TX underrun\n");
> >> >>
> >> >> + }
> >> >> +
> >> >> + /* Clear the pending irq by setting and then clearing it */
> >> >> + writel(clr, sdd->regs + S3C64XX_SPI_PENDING_CLR);
> >> >> + writel(clr & ~clr, sdd->regs + S3C64XX_SPI_PENDING_CLR);
> >> >
> >> > Wait, what? clr & ~clr == 0 Always. What are you actually
> >> > trying
> >> > to do here?
> >>
> >> The user manual says, wirting 1 to the pending clear register clears
> >> the interrupt (its not auto clear to 0). so i need to explicitly
> >> reset
> >> those bits thats what the 2nd write does
> >
> > I have looked through user's manuals of different Samsung SoCs. All of
> > them said that writing 1 to a bit clears the corresponding interrupt,
> > but none of them contain any note that it must be manually cleared to
> > 0.
> What i meant was the clear pending bit will not clear automatically.
> When I set the
> clear pending bit, it remains set. This is a problem for the next
> interrupt cycle.

How did you check that it does not clear automatically?

> > In addition the expression
> >
> > clr & ~clr
> >
> > makes no sense, because it is equal to 0.
>
> It makes sense, because we are not disturbing the interrupt pending
> bit at position 0, which is a trailing clr bit.

You either seem to misunderstand the problem I'm mentioning or not
understanding it at all.

If you take a variable named clr, no matter what value it is set to, and
you AND it with bitwise negation of the same variable, you will get 0.

See on this example:

Bits: 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0
-------------------------------
Values: 1 | 1 | 0 | 0 | 1 | 0 | 0 | 1
-------------------------------
Negation: 0 | 0 | 1 | 1 | 0 | 1 | 1 | 0
-------------------------------
AND: 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0

Now, can you see that (clr & ~clr) is the same as (0)?

Best regards,
Tomasz

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