Re: [PATCH 1/4] compiler.h: introduce unused_expression() macro

From: Andrew Morton
Date: Thu Apr 26 2012 - 18:34:13 EST


On Wed, 25 Apr 2012 15:26:23 +0400
Konstantin Khlebnikov <khlebnikov@xxxxxxxxxx> wrote:

> Sometimes we want to check some expressions correctness in compile-time without
> generating extra code. "(void)(e)" does not work if expression has side-effects.
> This patch introduces macro unused_expression() which helps in this situation.
>
> Cast to "long" required because sizeof does not work for bit-fields.
>
> Signed-off-by: Konstantin Khlebnikov <khlebnikov@xxxxxxxxxx>
> ---
> include/linux/compiler.h | 2 ++
> 1 file changed, 2 insertions(+)
>
> diff --git a/include/linux/compiler.h b/include/linux/compiler.h
> index 923d093..46fbda3 100644
> --- a/include/linux/compiler.h
> +++ b/include/linux/compiler.h
> @@ -310,4 +310,6 @@ void ftrace_likely_update(struct ftrace_branch_data *f, int val, int expect);
> */
> #define ACCESS_ONCE(x) (*(volatile typeof(x) *)&(x))
>
> +#define unused_expression(e) ((void)(sizeof((__force long)(e))))
> +

btw, please let's not add undocumented stuff, particularly obscure
undocumented stuff.

I typed this in:

--- a/include/linux/compiler.h~compilerh-introduce-unused_expression-macro-fix
+++ a/include/linux/compiler.h
@@ -310,6 +310,11 @@ void ftrace_likely_update(struct ftrace_
*/
#define ACCESS_ONCE(x) (*(volatile typeof(x) *)&(x))

+/*
+ * unused_expression() permits the compiler to check the validity of the
+ * expression but avoids the generation of any code, even if that expression
+ * has side-effects.
+ */
#define unused_expression(e) ((void)(sizeof((__force long)(e))))

#endif /* __LINUX_COMPILER_H */

but then decided I didn't want to apply the patches (yet?).
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