Re: Bug in scheduler when using rt_mutex

[Yong Zhang]

On Wed, Jan 19, 2011 at 11:43 AM, Mike Galbraith <efault@xxxxxx> wrote:
>> (cfs_rq->curr != se) equals to (!running), no?
>
> No, running is task_of(se) == rq->curr. ÂAnother class or fair group
> task may be rq_of(cfs_rq)->curr

If task_of(se) != rq->curr, as you said it maybe on another class or
fair group; then for its fair group, cfs_rq->curr == NULL.
cfs_rq->curr != se is always true.

Thanks,
Yong

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