They're wrong. The only constraint on the size of long (and I may
be making this up) is that sizeof(short) <= sizeof(int) <= sizeof(long)
(presumably the proprietary-but-about-to-be-standard long long will
have the constraint of sizeof(long) <= sizeof(long long), but here I
AM making things up.)
____
david parsons \bi/ sizeof long == 32 bits? Oh, my, those authors are
\/ going to have an expensive portability lesson.
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