>
>
>On Sat, 16 Jan 1999, Anthony Barbachan wrote:
>
>> Oh, so if I do not use any #defines or pointers in my C-"like" program
then
>> it isn't really C, its a subset. By the way there is a subsetted version
of
>> C++ out there, its Embedded C++ which removes the more costly features of
>> the language.
>
> What overhead is associated with pointers in C? Or preprocessor,
>for that matter? And if you hope to avoid pointers in the kernel - write
I never said this. I was saying that you stating that using only a subset
of C++ was not C++.
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