Re: [PATCH v1] iommu/vt-d: Remove the redundant logic in first_level_by_default()

From: Ethan Zhao
Date: Wed Jun 04 2025 - 03:25:53 EST




On 5/29/2025 2:11 PM, Tian, Kevin wrote:
From: Ethan Zhao <haifeng.zhao@xxxxxxxxxxxxxxx>
Sent: Thursday, May 29, 2025 1:48 PM

在 2025/5/23 16:10, Wei Wang 写道:
This original implementation included redundant logic to determine
whether
first-stage translation should be used by default. Simplify it and
preserve the original behavior:
- Returns false in legacy mode (no scalable mode support).
- Defaults to first-level translation when both FLTS and SLTS are
supported.

Signed-off-by: Wei Wang <wei.w.wang@xxxxxxxxx>
---
drivers/iommu/intel/iommu.c | 10 +---------
1 file changed, 1 insertion(+), 9 deletions(-)

diff --git a/drivers/iommu/intel/iommu.c b/drivers/iommu/intel/iommu.c
index cb0b993bebb4..228da47ab7cd 100644
--- a/drivers/iommu/intel/iommu.c
+++ b/drivers/iommu/intel/iommu.c
@@ -1366,15 +1366,7 @@ static void free_dmar_iommu(struct
intel_iommu *iommu)
*/
static bool first_level_by_default(struct intel_iommu *iommu)
{
- /* Only SL is available in legacy mode */
- if (!sm_supported(iommu))
- return false;
-
- /* Only level (either FL or SL) is available, just use it */
- if (ecap_flts(iommu->ecap) ^ ecap_slts(iommu->ecap))
- return ecap_flts(iommu->ecap);
-
- return true;

The function works like a digital circurt has 3 single bit inputs  sm,
flts, slts and one bit output ret.

so the true value table of the orignal function looks like

   sm   flts   slts    ret
a   0     x     x      false
b   1     1     0      true
c   1     0     1      false
d   1     1     1      true
e   1     0     0      true

'e' is actually wrong. We should not return true when the 1st level
cap doesn't exist.

If so, this patch should mention it fixes such case with fix tag, not
"removing the redundant logic with the same behavior".


Thanks,
Ethan


+ return sm_supported(iommu) && ecap_flts(iommu->ecap);

And the true value table of this new one looks like

   sm  flts slts    ret

f   1     1     x      true
g   1     0     x      false

h   0     1     x      false
i    0     0     x      false

so this table is correct.