Re: [PATCH v3] tools/memory-model: Make ppo a subrelation of po

From: Paul E. McKenney
Date: Sat Feb 25 2023 - 20:01:21 EST


On Fri, Feb 24, 2023 at 10:37:58AM -0800, Paul E. McKenney wrote:
> On Fri, Feb 24, 2023 at 10:32:43AM -0500, Alan Stern wrote:
> > On Fri, Feb 24, 2023 at 02:52:51PM +0100, Jonas Oberhauser wrote:
> > > As stated in the documentation and implied by its name, the ppo
> > > (preserved program order) relation is intended to link po-earlier
> > > to po-later instructions under certain conditions. However, a
> > > corner case currently allows instructions to be linked by ppo that
> > > are not executed by the same thread, i.e., instructions are being
> > > linked that have no po relation.
> > >
> > > This happens due to the mb/strong-fence/fence relations, which (as
> > > one case) provide order when locks are passed between threads
> > > followed by an smp_mb__after_unlock_lock() fence. This is
> > > illustrated in the following litmus test (as can be seen when using
> > > herd7 with `doshow ppo`):
> > >
> > > P0(int *x, int *y)
> > > {
> > > spin_lock(x);
> > > spin_unlock(x);
> > > }
> > >
> > > P1(int *x, int *y)
> > > {
> > > spin_lock(x);
> > > smp_mb__after_unlock_lock();
> > > *y = 1;
> > > }
> > >
> > > The ppo relation will link P0's spin_lock(x) and P1's *y=1, because
> > > P0 passes a lock to P1 which then uses this fence.
> > >
> > > The patch makes ppo a subrelation of po by letting fence contribute
> > > to ppo only in case the fence links events of the same thread.
> > >
> > > Signed-off-by: Jonas Oberhauser <jonas.oberhauser@xxxxxxxxxxxxxxx>
> > > ---
> > > tools/memory-model/linux-kernel.cat | 2 +-
> > > 1 file changed, 1 insertion(+), 1 deletion(-)
> > >
> > > diff --git a/tools/memory-model/linux-kernel.cat b/tools/memory-model/linux-kernel.cat
> > > index cfc1b8fd46da..adf3c4f41229 100644
> > > --- a/tools/memory-model/linux-kernel.cat
> > > +++ b/tools/memory-model/linux-kernel.cat
> > > @@ -82,7 +82,7 @@ let rwdep = (dep | ctrl) ; [W]
> > > let overwrite = co | fr
> > > let to-w = rwdep | (overwrite & int) | (addr ; [Plain] ; wmb)
> > > let to-r = (addr ; [R]) | (dep ; [Marked] ; rfi)
> > > -let ppo = to-r | to-w | fence | (po-unlock-lock-po & int)
> > > +let ppo = to-r | to-w | (fence & int) | (po-unlock-lock-po & int)
> > >
> > > (* Propagation: Ordering from release operations and strong fences. *)
> > > let A-cumul(r) = (rfe ; [Marked])? ; r
> >
> > Acked-by: Alan Stern <stern@xxxxxxxxxxxxxxxxxxx>
>
> Queued for the v6.4 merge window (not the current one), thank you both!

I tested both Alan's and Jonas's commit. These do not see to produce
any significant differences in behavior, which is of course a good thing.

Here are the differences and a few oddities:

auto/C-RR-G+RR-R+RR-G+RR-G+RR-R+RR-R+RR-R+RR-R.litmus

Timed out with changes, completed without them. But it completed
in 558.29 seconds against a limit of 600 seconds, so never mind.

auto/C-RR-G+RR-R+RR-R+RR-G+RR-R+RR-R+RR-G+RR-R.litmus

Timed out with changes, completed without them. But it completed
in 580.01 seconds against a limit of 600 seconds, so never mind. *

auto/C-RR-G+RR-R+RR-R+RR-R+RR-R+RR-G+RR-R+RR-R.litmus

Timed out with changes, completed without them. But it completed
in 522.29 seconds against a limit of 600 seconds, so never mind.

auto/C-RR-G+RR-R+RR-R+RR-R+RR-R+RR-G+RR-G+RR-R.litmus

Timed out with changes, completed without them. But it completed
in 588.70 seconds against a limit of 600 seconds, so never mind.

All tests that didn't time out matched Results comments.

The reason I am so cavalier about the times is that I was foolishly
running rcutorture concurrently with the new-version testing. I re-ran
and of them, only auto/C-RR-G+RR-R+RR-R+RR-G+RR-R+RR-R+RR-G+RR-R.litmus
timed out the second time. I re-ran it again, but without a time limit,
and it completed properly in 364.8 seconds compared to 580. A rerun
took 360.1 seconds. So things have slowed down a bit.

A few other oddities:

litmus/auto/C-LB-Lww+R-OC.litmus

Both versions flag a data race, which I am not seeing. It appears
to me that P1's store to u0 cannot happen unless P0's store
has completed. So what am I missing here?

litmus/auto/C-LB-Lrw+R-OC.litmus
litmus/auto/C-LB-Lww+R-Oc.litmus
litmus/auto/C-LB-Lrw+R-Oc.litmus
litmus/auto/C-LB-Lrw+R-A+R-Oc.litmus
litmus/auto/C-LB-Lww+R-A+R-OC.litmus

Ditto. (There are likely more.)

Thoughts?

Thanx, Paul