Re: [PATCH] tools/memory-model: Make ppo a subrelation of po

From: Jonas Oberhauser
Date: Tue Jan 24 2023 - 07:55:46 EST




On 1/23/2023 9:25 PM, Alan Stern wrote:
On Mon, Jan 23, 2023 at 07:25:48PM +0100, Jonas Oberhauser wrote:
Alright, after some synchronization in the other parts of this thread I am
beginning to prepare the next iteration of the patch.

On 1/19/2023 4:13 AM, Alan Stern wrote:
On Wed, Jan 18, 2023 at 10:38:11PM +0100, Jonas Oberhauser wrote:
On 1/18/2023 8:52 PM, Alan Stern wrote:
On Tue, Jan 17, 2023 at 08:31:59PM +0100, Jonas Oberhauser wrote:
- ([M] ; po? ; [LKW] ; fencerel(After-spinlock) ; [M]) |
- ([M] ; po ; [UL] ; (co | po) ; [LKW] ;
- fencerel(After-unlock-lock) ; [M])
+ ([M] ; po? ; [LKW] ; fencerel(After-spinlock) ; [M])
Shouldn't the po case of (co | po) remain intact here?
You can leave it here, but it is already covered by two other parts: the
ordering given through ppo/hb is covered by the po-unlock-lock-po & int in
ppo, and the ordering given through pb is covered by its inclusion in
strong-order.
What about the ordering given through
A-cumul(strong-fence)/cumul-fence/prop/hb? I suppose that might be
superseded by pb as well, but it seems odd not to have it in hb.
How should we resolve this?
My current favorite (compromise :D) solution would be to
1. still eliminate both po and co cases from first definition of
strong-fence which is used in ppo,
2. define a relation equal to the strong-order in this patch (with po|rf)
Wouldn't it need to have po|co? Consider:

Wx=1 Rx=1 Ry=1 Rz=1
lock(s) lock(s) lock(s)
unlock(s) unlock(s) unlock(s)
Wy=1 Wz=1 smp_mb__after_unlock_lock
Rx=0

With the co term this is forbidden. With only the rf term it is
allowed, because po-unlock-lock-po isn't A-cumulative.
No, but unlock() is ( https://git.kernel.org/pub/scm/linux/kernel/git/paulmck/linux-rcu.git/tree/tools/memory-model/lock.cat?h=dev.2023.01.19a#n67 ). So you get

  Rx=0 ->overwrite Wx=1  ->rfe Rx1 ->po-rel  T1:unlock(s) ->rfe T2:lock(s) ->po-unlock-lock-po;after ... fence;po Rx=0
which is
  Rx=0          ->prop ;                           po-unlock-lock-po;after ... fence;po Rx=0

Are you ok going forward like this then?

If not, I might prefer to redefine po-unlock-lock-po into something that works for all its use cases if possible. I think
|

po ; [UL] ; (po|co?;rf) ; [LKR] ; po

|might be such a definition but haven't fully thought about it.

best wishes, jonas