Re: [PATCH 11/13] x86_64: Remove pointless set_64bit() usage

[Peter Zijlstra]

On Sat, Nov 05, 2022 at 02:29:47PM +0100, Jason A. Donenfeld wrote:
> On Fri, Nov 04, 2022 at 10:15:08AM -0700, Linus Torvalds wrote:
> > On Fri, Nov 4, 2022 at 9:01 AM Peter Zijlstra <peterz@xxxxxxxxxxxxx> wrote:
> > >
> > > So cmpxchg_double() does a cmpxchg on a double long value and is
> > > currently supported by: i386, x86_64, arm64 and s390.
> > >
> > > On all those, except i386, two longs are u128.
> > >
> > > So how about we introduce u128 and cmpxchg128 -- then it directly
> > > mirrors the u64 and cmpxchg64 usage we already have. It then also
> > > naturally imposses the alignment thing.
> > 
> > Ack, except that we might have some "u128" users that do *not*
> > necessarily want any alignment thing.
> > 
> > But maybe we could at least start with an u128 type that is marked as
> > being fully aligned, and if some other user comes in down the line
> > that wants relaxed alignment we can call it "u128_unaligned" or
> > something.
> 
> Hm, sounds maybe not so nice for another use case: arithmetic code that
> makes use of u128 for efficient computations, but otherwise has
> no particular alignment requirements. For example, `typedef __uint128_t
> u128;` in:

Natural alignment is... natural. Making it unaligned is quite mad. That
whole u64 is not naturally aligned on i386 thing Linus referred to is a
sodding pain in the backside.

If the code has no alignment requirements, natural alignment is as good
as any. And if it does have requirements, you can use u128_unaligned.

Also:

$ ./align
16, 16

---

#include <stdio.h>

int main(int argx, char **argv)
{
	__int128 a;

	printf("%d, %d\n", sizeof(a), __alignof(a));
	return 0;
}