Re: [PATCH V5 16/25] perf/x86: Register hybrid PMUs

[Liang, Kan]

On 4/9/2021 2:58 AM, Peter Zijlstra wrote:
> On Mon, Apr 05, 2021 at 08:10:58AM -0700, kan.liang@xxxxxxxxxxxxxxx wrote:
> > @@ -2089,9 +2119,46 @@ static int __init init_hw_perf_events(void)
> >   	if (err)
> >   		goto out1;
> >   
> > -	err = perf_pmu_register(&pmu, "cpu", PERF_TYPE_RAW);
> > -	if (err)
> > -		goto out2;
> > +	if (!is_hybrid()) {
> > +		err = perf_pmu_register(&pmu, "cpu", PERF_TYPE_RAW);
> > +		if (err)
> > +			goto out2;
> > +	} else {
> > +		u8 cpu_type = get_this_hybrid_cpu_type();
> > +		struct x86_hybrid_pmu *hybrid_pmu;
> > +		bool registered = false;
> > +		int i;
> > +
> > +		if (!cpu_type && x86_pmu.get_hybrid_cpu_type)
> > +			cpu_type = x86_pmu.get_hybrid_cpu_type();
> > +
> > +		for (i = 0; i < x86_pmu.num_hybrid_pmus; i++) {
> > +			hybrid_pmu = &x86_pmu.hybrid_pmu[i];
> > +
> > +			hybrid_pmu->pmu = pmu;
> > +			hybrid_pmu->pmu.type = -1;
> > +			hybrid_pmu->pmu.attr_update = x86_pmu.attr_update;
> > +			hybrid_pmu->pmu.capabilities |= PERF_PMU_CAP_HETEROGENEOUS_CPUS;
> > +
> > +			err = perf_pmu_register(&hybrid_pmu->pmu, hybrid_pmu->name,
> > +						(hybrid_pmu->cpu_type == hybrid_big) ? PERF_TYPE_RAW : -1);
> > +			if (err)
> > +				continue;
> > +
> > +			if (cpu_type == hybrid_pmu->cpu_type)
> > +				x86_pmu_update_cpu_context(&hybrid_pmu->pmu, raw_smp_processor_id());
> > +
> > +			registered = true;
> > +		}
> > +
> > +		if (!registered) {
> > +			pr_warn("Failed to register hybrid PMUs\n");
> > +			kfree(x86_pmu.hybrid_pmu);
> > +			x86_pmu.hybrid_pmu = NULL;
> > +			x86_pmu.num_hybrid_pmus = 0;
> > +			goto out2;
> > +		}
>
> I don't think this is quite right. registered will be true even if one
> fails, while I think you meant to only have it true when all (both)
> types registered correctly.

No, I mean that perf error out only when all types fail to be registered.

For the case (1 failure, 1 success), users can still access the 
registered PMU.
When a CPU belongs to the unregistered PMU online, a warning will be 
displayed. Because in init_hybrid_pmu(), we will check the PMU type 
before update the CPU mask.

        if (WARN_ON_ONCE(!pmu || (pmu->pmu.type == -1))) {
                cpuc->pmu = NULL;
                return false;
        }


Thanks,
Kan