[PATCH] Fix ld-version.sh script if LLD was built with LLD_VENDOR

[Bernhard Rosenkränzer]

If LLD was built with -DLLD_VENDOR="xyz", ld.lld --version output
will prefix LLD_VENDOR. Since LLD_VENDOR can contain spaces, the
LLD identifier isn't guaranteed to be $2 either.

Adjust the version checker to handle such versions of lld.

Signed-off-by: Bernhard Rosenkränzer <bero@xxxxxxxxx>
---
 scripts/ld-version.sh | 12 ++++++++++++
 1 file changed, 12 insertions(+)

diff --git a/scripts/ld-version.sh b/scripts/ld-version.sh
index a463273509b5..4c042a306e22 100755
--- a/scripts/ld-version.sh
+++ b/scripts/ld-version.sh
@@ -49,6 +49,18 @@ elif [ "$1" = LLD ]; then
 	min_version=$lld_min_version
 	name=LLD
 	disp_name=LLD
+elif echo "$@" |grep -q ' LLD '; then
+	# if LLD was built with -DLLD_VENDOR="xyz", it ld.lld --version
+	# says "xyz LLD [...]". Since LLD_VENDOR may contain spaces, we
+	# don't know the exact position of "LLD" and the version info
+	# at this point
+	while [ "$1" != "LLD" ]; do
+		shift
+	done
+	version=$2
+	min_version=$lld_min_version
+	name=LLD
+	disp_name=LLD
 else
 	echo "$orig_args: unknown linker" >&2
 	exit 1
-- 
2.30.1