[PATCH 3.16 044/202] fuse: call pipe_buf_release() under pipe lock

From: Ben Hutchings
Date: Sat Apr 27 2019 - 11:26:41 EST


3.16.66-rc1 review patch. If anyone has any objections, please let me know.

------------------

From: Jann Horn <jannh@xxxxxxxxxx>

commit 9509941e9c534920ccc4771ae70bd6cbbe79df1c upstream.

Some of the pipe_buf_release() handlers seem to assume that the pipe is
locked - in particular, anon_pipe_buf_release() accesses pipe->tmp_page
without taking any extra locks. From a glance through the callers of
pipe_buf_release(), it looks like FUSE is the only one that calls
pipe_buf_release() without having the pipe locked.

This bug should only lead to a memory leak, nothing terrible.

Fixes: dd3bb14f44a6 ("fuse: support splice() writing to fuse device")
Signed-off-by: Jann Horn <jannh@xxxxxxxxxx>
Signed-off-by: Miklos Szeredi <mszeredi@xxxxxxxxxx>
[bwh: Backported to 3.16: adjust context]
Signed-off-by: Ben Hutchings <ben@xxxxxxxxxxxxxxx>
---
fs/fuse/dev.c | 2 ++
1 file changed, 2 insertions(+)

--- a/fs/fuse/dev.c
+++ b/fs/fuse/dev.c
@@ -1978,10 +1978,12 @@ static ssize_t fuse_dev_splice_write(str

ret = fuse_dev_do_write(fc, &cs, len);

+ pipe_lock(pipe);
for (idx = 0; idx < nbuf; idx++) {
struct pipe_buffer *buf = &bufs[idx];
buf->ops->release(pipe, buf);
}
+ pipe_unlock(pipe);
out:
kfree(bufs);
return ret;