Re: [PATCH 1/1] epoll: remove wrong assert that ep_poll_callback is always called with irqs off

From: Roman Penyaev
Date: Tue Jan 08 2019 - 07:42:31 EST


On 2019-01-08 11:01, Roman Penyaev wrote:
That was wrong assumption that all drivers disable irqs before waking up
a wait queue. Even assert line is removed the whole logic stays correct:
epoll always locks rwlock with irqs disabled and by itself does not call
from interrupts, thus it is up to driver how to call wake_up_locked(),
because if driver does not handle any interrupts (like fuse in the the
report) of course it is safe on its side to take a simple spin_lock.

This is wrong and can lead to dead lock: we always call read_lock(), caller
can call us with irqs enabled. Another driver, which also calls
ep_poll_callback(), can be called from interrupt context (irqs disabled)
thus it can interrupt the one who does not disable irqs. Even we take
a read_lock() (which should be fine to interrupt), write_lock(), which
comes in the middle, can cause a dead lock:

#CPU0 #CPU1

task: task: irq:

spin_lock(&wq1->lock);
ep_poll_callback():
read_lock(&ep->lock)
....
write_lock_irq(&ep->lock) ....
#waits reads .... >>>>>>>>>>>>>> IRQ CPU1
spin_lock_irqsave(&wq2->lock)
ep_poll_callback():
read_lock(&ep->lock);
# to avoid write starve should
# wait writer to finish, thus
# dead lock


What we can do:

a) disable irqs if we are not in interrupt.
b) revert the patch completely.

David, is it really crucial in terms of performance to avoid double
local_irq_save() on Xen on this ep_poll_callback() hot path?

For example why not to do the following:

if (!in_interrupt())
local_irq_save(flags);
read_lock(ep->lock);

with huge comment explaining performance number.

Or just give up and simply revert the original patch completely
and always call read_lock_irqsave().

--
Roman