Re: [PATCH v2 2/2] arm64: uaccess: Implement unsafe accessors

From: Julien Thierry
Date: Fri Dec 07 2018 - 03:38:17 EST




On 12/06/2018 06:25 PM, Catalin Marinas wrote:
On Mon, Dec 03, 2018 at 01:55:18PM +0000, Julien Thierry wrote:
diff --git a/arch/arm64/include/asm/uaccess.h b/arch/arm64/include/asm/uaccess.h
index 07c3408..cabfcae 100644
--- a/arch/arm64/include/asm/uaccess.h
+++ b/arch/arm64/include/asm/uaccess.h
@@ -233,6 +233,23 @@ static inline void uaccess_enable_not_uao(void)
__uaccess_enable(ARM64_ALT_PAN_NOT_UAO);
}
+#define unsafe_user_region_active uaccess_region_active
+static inline bool uaccess_region_active(void)
+{
+ if (system_uses_ttbr0_pan()) {
+ u64 ttbr;
+
+ ttbr = read_sysreg(ttbr1_el1);
+ return ttbr & TTBR_ASID_MASK;

Nitpick: could write this in 1-2 lines.


True, I can do that in 1 line.

+ } else if (cpus_have_const_cap(ARM64_ALT_PAN_NOT_UAO)) {
+ return (read_sysreg(sctlr_el1) & SCTLR_EL1_SPAN) ?
+ false :
+ !read_sysreg_s(SYS_PSTATE_PAN);
+ }

ARM64_ALT_PAN_NOT_UAO implies ARM64_HAS_PAN which implies SCTLR_EL1.SPAN
is 0 at run-time. Is this to cope with the case of being called prior to
cpu_enable_pan()?


Yes, the issue I can into is that for cpufeatures, .cpu_enable() callbacks are called inside stop_machine() which obviously might_sleep and so attempts to check whether user_access is on. But for features that get enabled before PAN, the PAN bit will be set.

Thanks,

Julien