Re: [PATCH v3 03/10] sched/topology: Provide cfs_overload_cpus bitmap

From: Steven Sistare
Date: Mon Nov 26 2018 - 14:07:03 EST


On 11/20/2018 7:42 AM, Valentin Schneider wrote:
> On 19/11/2018 17:33, Steven Sistare wrote:
> [...]
>>>
>>> Thinking about misfit stealing, we can't use the sd_llc_shared's because
>>> on big.LITTLE misfit migrations happen across LLC domains.
>>>
>>> I was thinking of adding a misfit sparsemask to the root_domain, but
>>> then I thought we could do the same thing for cfs_overload_cpus.
>>>
>>> By doing so we'd have a single source of information for overloaded CPUs,
>>> and we could filter that down during idle balance - you mentioned earlier
>>> wanting to try stealing at each SD level. This would also let you get
>>> rid of [PATCH 02].
>>>
>>> The main part of try_steal() could then be written down as something like
>>> this:
>>>
>>> ----->8-----
>>>
>>> for_each_domain(this_cpu, sd) {
>>> span = sched_domain_span(sd)
>>>
>>> for_each_sparse_wrap(src_cpu, overload_cpus) {
>>> if (cpumask_test_cpu(src_cpu, span) &&
>>> steal_from(dts_rq, dst_rf, &locked, src_cpu)) {
>>> stolen = 1;
>>> goto out;
>>> }
>>> }
>>> }
>>>
>>> ------8<-----
>>>
>>> We could limit the stealing to stop at the highest SD_SHARE_PKG_RESOURCES
>>> domain for now so there would be no behavioural change - but we'd
>>> factorize the #ifdef SCHED_SMT bit. Furthermore, the door would be open
>>> to further stealing.
>>>
>>> What do you think?
>>
>> That is not efficient for a multi-level search because at each domain level we
>> would (re) iterate over overloaded candidates that do not belong in that level.
>
>
> Mmm I was thinking we could abuse the wrap() and start at
> (fls(prev_span) + 1), but we're not guaranteed to have contiguous spans -
> the Arm Juno for instance has [0, 3, 4], [1, 2] as MC-level domains, so
> that goes down the drain.
>
> Another thing that has been trotting in my head would be some helper to
> create a cpumask from a sparsemask (some sort of sparsemask_span()),
> which would let us use the standard mask operators:
>
> ----->8-----
> struct cpumask *overload_span = sparsemask_span(overload_cpus)
>
> for_each_domain(this_cpu, sd)
> for_each_cpu_and(src_cpu, overload_span, sched_domain_span(sd))
> <steal_from here>
> -----8>-----
>
> The cpumask could be part of the sparsemask struct to save us the
> allocation, and only updated when calling sparsemask_span().

I thought of providing something like this along with other sparsemask
utility functions, but I decided to be minimalist, and let others add
more functions if/when they become needed. this_cpu_cpumask_var_ptr(select_idle_mask)
is a temporary that could be used as the destination of the conversion.

Also, conversion adds cost, particularly on larger systems. When comparing a
cpumask and a sparsemask, it is more efficient to iterate over the smaller
set, and test for membership in the larger, such as in try_steal:

for_each_cpu(src_cpu, cpu_smt_mask(dst_cpu)) {
if (sparsemask_test_elem(src_cpu, overload_cpus)

>> To extend stealing across LLC, I would like to keep the per-LLC sparsemask,
>> but add to each SD a list of sparsemask pointers. The list nodes would be
>> private, but the sparsemask structs would be shared. Each list would include
>> the masks that overlap the SD's members. The list would be a singleton at the
>> core and LLC levels (same as the socket level for most processors), and would
>> have multiple elements at the NUMA level.
>
> I see. As for misfit, creating asym_cpucapacity siblings of the sd_llc_*()
> functions seems a bit much - there'd be a lot of redundancy for basically
> just a single shared sparsemask, which is why I was rambling about moving
> things to root_domain.
>
> Having different locations where sparsemasks are stored is a bit of a
> pain which I'd like to avoid, but if it can't be unified I suppose we'll
> have to live with it.

I don't follow. A per-LLC sparsemask representing misfits can be allocated with
one more line in sd_llc_alloc, and you can steal across LLC using the list I
briefly described above.

- Steve