Re: [PATCH] kernel: audit_tree: Fix a sleep-in-atomic-context bug

From: Matthew Wilcox
Date: Thu Jun 21 2018 - 00:29:37 EST


On Thu, Jun 21, 2018 at 11:32:45AM +0800, Jia-Ju Bai wrote:
> The kernel may sleep with holding a spinlock.
> The function call paths (from bottom to top) in Linux-4.16.7 are:
>
> [FUNC] kmem_cache_alloc(GFP_KERNEL)
> fs/notify/mark.c, 439:
> kmem_cache_alloc in fsnotify_attach_connector_to_object
> fs/notify/mark.c, 520:
> fsnotify_attach_connector_to_object in fsnotify_add_mark_list
> fs/notify/mark.c, 590:
> fsnotify_add_mark_list in fsnotify_add_mark_locked
> kernel/audit_tree.c, 437:
> fsnotify_add_mark_locked in tag_chunk
> kernel/audit_tree.c, 423:
> spin_lock in tag_chunk

There are several locks here; your report would be improved by saying
which one is the problem. I'm assuming it's old_entry->lock.

spin_lock(&old_entry->lock);
...
if (fsnotify_add_inode_mark_locked(chunk_entry,
old_entry->connector->inode, 1)) {
...
return fsnotify_add_mark_locked(mark, inode, NULL, allow_dups);
...
ret = fsnotify_add_mark_list(mark, inode, mnt, allow_dups);
...
if (inode)
connp = &inode->i_fsnotify_marks;
conn = fsnotify_grab_connector(connp);
if (!conn) {
err = fsnotify_attach_connector_to_object(connp, inode, mnt);

It seems to me that this is safe because old_entry is looked up from
fsnotify_find_mark, and it can't be removed while its lock is held.
Therefore there's always a 'conn' returned from fsnotify_grab_connector(),
and so this path will never be taken.

But this code path is confusing to me, and I could be wrong. Jan, please
confirm my analysis is correct?

> [FUNC] kmem_cache_alloc(GFP_KERNEL)
> fs/notify/mark.c, 439:
> kmem_cache_alloc in fsnotify_attach_connector_to_object
> fs/notify/mark.c, 520:
> fsnotify_attach_connector_to_object in fsnotify_add_mark_list
> fs/notify/mark.c, 590:
> fsnotify_add_mark_list in fsnotify_add_mark_locked
> kernel/audit_tree.c, 291:
> fsnotify_add_mark_locked in untag_chunk
> kernel/audit_tree.c, 258:
> spin_lock in untag_chunk

I'm just going to assume this one is the same.