Re: Re: Re: [PATCH] usb: core: fix a double free in the usb driver

From: Alan Stern
Date: Fri Jun 03 2016 - 10:28:13 EST


On Fri, 3 Jun 2016, Chung-Geol Kim wrote:

> Yes, you are right, The presentational errors in order to obtain an understanding of the process.
> Therefore, I will be happy to explain again the diagrammatic representation as shown below.
> If using usb 3.0 storage(OTG), you can see as below.
>
> ==============================================
> At *Insert USB(3.0) Storage
> sequence <1> --> <5>
> ==============================================
> VOLD
> =================================|============
> (uevent)
> ______|___________
> |<5> |
> | SCSI |
> |usb_get_hcd |
> |shared_hcd(kref=3)|
> |__________________|
> ___________________ ________|_________
> |<2> | |<4> |
> |dwc3_otg_sm_work | |dwc3_otg_sm_work |
> |usb_get_hcd | |usb_get_hcd |
> |primary_hcd(kref=2)| |shared_hcd(kref=2)|
> |___________________| |__________________|
> _________|_________ ________|_________
> |<1> | |<3> |
> |New USB BUS #1 | |New USB BUS #2 |
> |usb_create_hcd | |usb_create_hcd |
> |primary_hcd(kref=1)| |shared_hcd(kref=1)|
> | | | |
> |bandXX_mutex(alloc)|<-(Link)-bandXX_mutex |
> |___________________| |__________________|
>

When people present diagrams like this, the universal convention is to
show earlier times at the top and later times at the bottom. That way
the order in which you read the diagram is the same as the order in
which the events are supposed to occur.

Also, the convention is to put events next to each other if they happen
at the same time. In your diagram, <1> and <3> are next to each other
but they don't happen at the same time.

> ==============================================
> At *remove USB(3.0) Storage
> sequence <1> --> <5> ((Normal Case))
> ==============================================
> VOLD
> =================================|============
> (uevent)
> ______|___________
> |<1> |
> | SCSI |
> |usb_put_hcd |
> |shared_hcd(kref=2)|
> |__________________|
> ___________________ ________|_________
> |<4> | |<2> |
> |dwc3_otg_sm_work | |dwc3_otg_sm_work |
> |usb_put_hcd | |usb_put_hcd |
> |primary_hcd(kref=1)| |shared_hcd(kref=1)|
> |___________________| |__________________|
> _________|_________ ________|_________
> |<5> | |<3> |
> |New USB BUS #1 | |New USB BUS #2 |
> |hcd_release | |hcd_release |
> |primary_hcd(kref=0)| |shared_hcd(kref=0)|
> | | | |
> |bandXX_mutex(free) | -X-cut off)-bandXX_mutex|
> |___________________| |__________________|
>
> ----------------------------------------------

> >The real bug here is that the shared_hcd is released after the
> >primary_hcd. That's what you need to fix.
>
> NO, It 's only depend on vold(scsi) release time.
> If the vold later released and is being released first hcd,
> Double free happened at <5> as below.
>
> ==============================================
> At *remove USB(3.0) Storage
> sequence <1> --> <5> ((Problem Case))
> ==============================================
> VOLD
> =================================|============
> (uevent)
> ______|___________
> |<5> |
> | SCSI |
> |usb_put_hcd |
> |shared_hcd(kref=0)|
> |*hcd_release |
> |bandXX_mutex(free*)|<- double free
> |__________________|
> ___________________ ________|_________
> |<3> | |<1> |
> |dwc3_otg_sm_work | |dwc3_otg_sm_work |
> |usb_put_hcd | |usb_put_hcd |
> |primary_hcd(kref=1)| |shared_hcd(kref=2)|
> |___________________| |__________________|
> _________|_________ ________|_________
> |<4> | |<2> |
> |New USB BUS #1 | |New USB BUS #2 |
> |hcd_release | | |
> |primary_hcd(kref=0)| |shared_hcd(kref=1)|
> | | | |
> |bandXX_mutex(free) |<-(Link)-bandXX_mutex |
> |___________________| |__________________|
>
> ----------------------------------------------

That's the same as what I said. In your diagram, vold releases the
shared_hcd (in <5>) after dwc3_otg_sm_work releases the primary_hcd
(in <4>).

If you change the code so that the shared_hcd takes a reference to the
primary_hcd and drops that reference when the shared_hcd is released,
this will never occur.

Alan Stern