Re: [PATCH 1/5] clk: allow reentrant calls into the clk framework

From: Russell King - ARM Linux
Date: Mon Mar 18 2013 - 17:00:31 EST


On Mon, Mar 18, 2013 at 01:15:51PM -0700, Mike Turquette wrote:
> Quoting Ulf Hansson (2013-02-28 01:54:34)
> > On 28 February 2013 05:49, Mike Turquette <mturquette@xxxxxxxxxx> wrote:
> > > @@ -703,10 +744,29 @@ int clk_enable(struct clk *clk)
> > > unsigned long flags;
> > > int ret;
> > >
> > > + /* this call re-enters if it is from the same context */
> > > + if (spin_is_locked(&enable_lock) || mutex_is_locked(&prepare_lock)) {
> > > + if ((void *) atomic_read(&context) == get_current()) {
> > > + ret = __clk_enable(clk);
> > > + goto out;
> > > + }
> > > + }
> >
> > I beleive the clk_enable|disable code will be racy. What do you think
> > about this scenario:
> >
> > 1. Thread 1, calls clk_prepare -> clk is not reentrant -> mutex_lock
> > -> set_context to thread1.
> > 2. Thread 2, calls clk_enable -> above "if" will mean that get_current
> > returns thread 1 context and then clk_enable continues ->
> > spin_lock_irqsave -> set_context to thread 2.
> > 3. Thread 1 continues and triggers a reentancy for clk_prepare -> clk
> > is not reentrant (since thread 2 has set a new context) -> mutex_lock
> > and we will hang forever.
> >
> > Do you think above scenario could happen?
> >
> > I think the solution would be to invent another "static atomic_t
> > context;" which is used only for fast path functions
> > (clk_enable|disable). That should do the trick I think.
>
> Ulf,
>
> You are correct. In fact I have a branch that has two separate context
> pointers, one for mutex-protected functions and one for
> spinlock-protected functions. Somehow I managed to discard that change
> before settling on the final version that was published.

Err.

Do not forget one very important point.

Any clock which has clk_enable() called on it must have had clk_prepare()
already called _and_ completed. A second clk_prepare() call on the same
clock should be a no-op other than to increase the prepare reference count
on it.

If you do anything else, you are going to get into sticky problems.
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