RE: [PATCH] x86_dump_trace: avoiding endless " <IRQ> " is printed

From: Liu, Chuansheng
Date: Wed Aug 15 2012 - 21:05:51 EST



> The endless " <IRQ> " is as below:
> ...
> [ 82.215244,0] <IRQ>
> [ 82.215399,0] <IRQ>
> [ 82.215554,0] <IRQ>
> [ 82.215710,0] <IRQ>
> [ 82.215865,0] <IRQ>
> [ 82.216022,0] <IRQ>
> [ 82.216178,0] <IRQ>
> [ 82.216333,0] <IRQ>
> [ 82.216488,0] <IRQ>
> [ 82.216643,0] <IRQ>
> [ 82.216798,0] <IRQ>
> [ 82.216953,0] <IRQ>
> ...
>
Anyone can give some help for the above logs? It is the real case we meet on our x86_32 platform.
I checked the code, the tons of " <IRQ> " should be printed from the below code in dumpstack_32.c:
[if (ops->stack(data, "IRQ") < 0)] will print " <IRQ> ", as for the endless printing, it should be for(;;) is not
broken, so I guess in this case context->previous_esp == context.

But from code review, previous_esp is just set at hardirq. No possible this case happening.
Who can give help? Thanks.

void dump_trace(struct task_struct *task, struct pt_regs *regs,
unsigned long *stack, unsigned long bp,
const struct stacktrace_ops *ops, void *data)
{
for (;;) {
struct thread_info *context;

context = (struct thread_info *)
((unsigned long)stack & (~(THREAD_SIZE - 1)));
bp = ops->walk_stack(context, stack, bp, ops, data, NULL, &graph);

stack = (unsigned long *)context->previous_esp;
if (!stack)
break;
if (ops->stack(data, "IRQ") < 0) == > Here printing the " <IRQ> "
break;
touch_nmi_watchdog();
}
}

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