Re: workqueue_set_max_active(wq, 0)?

From: Tejun Heo
Date: Thu Dec 15 2011 - 13:35:48 EST


Hello, Johannes.

On Thu, Dec 15, 2011 at 04:38:12PM +0100, Johannes Berg wrote:
> --- a/kernel/workqueue.c 2011-12-10 17:32:26.000000000 +0100
> +++ b/kernel/workqueue.c 2011-12-15 16:36:06.000000000 +0100
> @@ -51,6 +51,7 @@ enum {
> GCWQ_DISASSOCIATED = 1 << 2, /* cpu can't serve workers */
> GCWQ_FREEZING = 1 << 3, /* freeze in progress */
> GCWQ_HIGHPRI_PENDING = 1 << 4, /* highpri works on queue */
> + GCWQ_PAUSING = 1 << 5,

Hmmm... confused. Pausing is per-wq, why is this flag on gcwq?
Shouldn't it be on workqueue_struct?

> +void pause_workqueue(struct workqueue_struct *wq)
> +{
> + unsigned int cpu;
> +
> + for_each_cwq_cpu(cpu, wq) {
> + struct cpu_workqueue_struct *cwq = get_cwq(cpu, wq);
> + struct global_cwq *gcwq = cwq->gcwq;
> +
> + spin_lock_irq(&gcwq->lock);
> +
> + WARN_ON(gcwq->flags & GCWQ_PAUSING);
> + gcwq->flags |= GCWQ_PAUSING;
> +
> + cwq->max_active = 0;
> +
> + spin_unlock_irq(&gcwq->lock);
> + }
> +
> + wait_event(wq->waitq, count_active(wq) == 0);
> +}
> +EXPORT_SYMBOL(pause_workqueue);

What if there are multiple callers of this function on the same wq?
Maybe something like wq->pause_depth and also use it from freeze path?

> +void resume_workqueue(struct workqueue_struct *wq)
> +{
> + unsigned int cpu;
> +
> + for_each_cwq_cpu(cpu, wq) {
> + struct cpu_workqueue_struct *cwq = get_cwq(cpu, wq);
> + struct global_cwq *gcwq = cwq->gcwq;
> +
> + spin_lock_irq(&gcwq->lock);
> +
> + WARN_ON(!(gcwq->flags & GCWQ_PAUSING));
> + gcwq->flags &= ~GCWQ_PAUSING;
> +
> + cwq->max_active = wq->saved_max_active;
> +
> + wake_up_worker(gcwq);
> + spin_unlock_irq(&gcwq->lock);
> + }
> +}
> +EXPORT_SYMBOL(resume_workqueue);

I don't think wake_up_worker() would be sufficient.
cwq_activate_first_delayed() needs to be called to kick the delayed
work items.

I think it would be great if this can be abstracted out so that both
the freezer and explicit pausing use the same facility. They aren't
that different after all.

Thanks.

--
tejun
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