[PATCH 1/2] proc/insterrupts: make it cpu hotplug safe

[Yong Zhang]

KOSAKI Motonhiro noticed that the reader of /proc/interrupts
could be preempted by cpu hotplug, thus the reader can get
broken result due to show_interrupts() iterate every online
cpu without any protection.

Signed-off-by: Yong Zhang <yong.zhang0@xxxxxxxxx>
Cc: Andrew Morton <akpm@xxxxxxxxxxxxxxxxxxxx>
Cc: Keika Kobayashi <kobayashi.kk@xxxxxxxxxxxxxx>
Cc: KOSAKI Motohiro <kosaki.motohiro@xxxxxxxxxxxxxx>
Cc: Heiko Carstens <heiko.carstens@xxxxxxxxxx>
---
 fs/proc/interrupts.c |   10 +++++++++-
 1 files changed, 9 insertions(+), 1 deletions(-)

diff --git a/fs/proc/interrupts.c b/fs/proc/interrupts.c
index 05029c0..d5642a6 100644
--- a/fs/proc/interrupts.c
+++ b/fs/proc/interrupts.c
@@ -4,6 +4,7 @@
 #include <linux/irqnr.h>
 #include <linux/proc_fs.h>
 #include <linux/seq_file.h>
+#include <linux/cpu.h>
 
 /*
  * /proc/interrupts
@@ -35,14 +36,21 @@ static const struct seq_operations int_seq_ops = {
 
 static int interrupts_open(struct inode *inode, struct file *filp)
 {
+	get_online_cpus();
 	return seq_open(filp, &int_seq_ops);
 }
 
+static int interrupts_release(struct inode *inode, struct file *filp)
+{
+	put_online_cpus();
+	return seq_release(inode, filp);
+}
+
 static const struct file_operations proc_interrupts_operations = {
 	.open		= interrupts_open,
 	.read		= seq_read,
 	.llseek		= seq_lseek,
-	.release	= seq_release,
+	.release	= interrupts_release,
 };
 
 static int __init proc_interrupts_init(void)
-- 
1.7.4.1

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