Is kernel optimized with dead store removal?

[Roel Kluin]

According to http://cwe.mitre.org/data/slices/2000.html#14 due to optimization
A call to memset() can be removed as a dead store when the buffer is not used
after its value is overwritten. Does this optimization also occur during
compilation of the Linux kernel? Then I think I may have found some
vulnerabilities. One is sha1_update() where memset(temp, 0, sizeof(temp)); may
be removed.

Roel
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