Re: [PATCH] audit: Call tty_audit_push_task() outside preemptdisabled region

[Oleg Nesterov]

On 12/01, Thomas Gleixner wrote:
>
> -void tty_audit_push_task(struct task_struct *tsk, uid_t loginuid, u32 sessionid)
> +int tty_audit_push_task(struct task_struct *tsk, uid_t loginuid, u32 sessionid)
>  {
> -	struct tty_audit_buf *buf;
> +	struct tty_audit_buf *buf = NULL;
> +	unsigned long flags;
>
> -	spin_lock_irq(&tsk->sighand->siglock);
> -	buf = tsk->signal->tty_audit_buf;
> -	if (buf)
> +	if (!lock_task_sighand(tsk, &flags))
> +		return -ESRCH;
> +
> +	if (tsk->signal->audit_tty && tsk->signal->tty_audit_buf) {
> +		buf = tsk->signal->tty_audit_buf;
>  		atomic_inc(&buf->count);
> -	spin_unlock_irq(&tsk->sighand->siglock);
> +	}
> +	unlock_task_sighand(tsk, &flags);
> +
>  	if (!buf)
> -		return;
> +		return -EPERM;

I think the patch is correct, but it changes the behaviour of
audit_prepare_user_tty() a bit.

Suppose that signal->audit_tty != NULL but signal->tty_audit_buf
is not allocated yet. In this audit_prepare_user_tty() returns 0
before the patch and -EPERM after.

I do not know if this matters, just to be sure this is OK.

Oleg.

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