Remove duplicate code from sched_fair.c

[Balbir Singh]

yield_task_fair has some duplicate code, that can be replaced with
rb_last(). This code reuses rb_next and removes the duplicate code.
As a side effect, we don't do an rb_entry for each node as we walk
along the path.

Comments, flames?

Description
-----------

pick_task_entity() duplicates existing code. This functionality can be easily
obtained using rb_last(). Avoid code duplication by using rb_last()

Signed-off-by: Balbir Singh <balbir@xxxxxxxxxxxxxxxxxx>
---

 kernel/sched_fair.c |   15 ++++++---------
 1 file changed, 6 insertions(+), 9 deletions(-)

diff -puN kernel/sched_fair.c~use-existing-code-in-sched-yield kernel/sched_fair.c
--- linux-2.6.25-rc2/kernel/sched_fair.c~use-existing-code-in-sched-yield	2008-02-22 11:35:35.000000000 +0530
+++ linux-2.6.25-rc2-balbir/kernel/sched_fair.c	2008-02-22 11:50:03.000000000 +0530
@@ -301,16 +301,13 @@ static struct sched_entity *__pick_next_
 
 static inline struct sched_entity *__pick_last_entity(struct cfs_rq *cfs_rq)
 {
-	struct rb_node **link = &cfs_rq->tasks_timeline.rb_node;
-	struct sched_entity *se = NULL;
-	struct rb_node *parent;
-
-	while (*link) {
-		parent = *link;
-		se = rb_entry(parent, struct sched_entity, run_node);
-		link = &parent->rb_right;
-	}
+	struct rb_node *last;
+	struct sched_entity *se;
 
+	last = rb_last(&cfs_rq->tasks_timeline);
+	if (!last)
+		return NULL;
+	se = rb_entry(last, struct sched_entity, run_node);
 	return se;
 }
 
_

-- 
	Warm Regards,
	Balbir Singh
	Linux Technology Center
	IBM, ISTL
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