Re: [PATCH] arch_ptrace_stop

From: Oleg Nesterov
Date: Thu Dec 13 2007 - 12:28:45 EST


Roland McGrath wrote:
>
> +static int sigkill_pending(struct task_struct *tsk)
> +{
> + return ((sigismember(&tsk->pending.signal, SIGKILL) ||
> + sigismember(&tsk->signal->shared_pending.signal, SIGKILL)) &&
> + !unlikely(sigismember(&tsk->blocked, SIGKILL)));
> +}

How is it possible that SIGKILL is blocked?

> static void ptrace_stop(int exit_code, int nostop_code, siginfo_t *info)
> {
> + int killed = 0;
> +
> + if (arch_ptrace_stop_needed(exit_code, info)) {
> + /*
> + * The arch code has something special to do before a
> + * ptrace stop. This is allowed to block, e.g. for faults
> + * on user stack pages. We can't keep the siglock while
> + * calling arch_ptrace_stop, so we must release it now.
> + * To preserve proper semantics, we must do this before
> + * any signal bookkeeping like checking group_stop_count.
> + * Meanwhile, a SIGKILL could come in before we retake the
> + * siglock. That must prevent us from sleeping in TASK_TRACED.
> + * So after regaining the lock, we must check for SIGKILL.
> + */
> + spin_unlock_irq(&current->sighand->siglock);
> + arch_ptrace_stop(exit_code, info);
> + spin_lock_irq(&current->sighand->siglock);
> + killed = sigkill_pending(current);
> + }
> +
> /*
> * If there is a group stop in progress,
> * we must participate in the bookkeeping.
> @@ -1604,7 +1635,7 @@ static void ptrace_stop(int exit_code, i
> spin_unlock_irq(&current->sighand->siglock);
> try_to_freeze();
> read_lock(&tasklist_lock);
> - if (may_ptrace_stop()) {
> + if (!unlikely(killed) && may_ptrace_stop()) {

Could you please explain this change in more details?

Currently ptrace_stop() schedules in TASK_TRACED state even if we have a
pending SIGKILL. With this patch this is still possible, but unless
arch_ptrace_stop_needed() is true and thus we will check sigkill_pending().

Suppose the task was SIGKILL'ed and does ptrace_notify(PTRACE_EVENT_EXIT),
now the resulting action depends on arch_ptrace_stop_needed().

I don't claim this is wrong, just trying to understand.

Thanks,

Oleg.

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