Re: [PATCH] Make access to task's nsproxy liter

[Pavel Emelyanov]

Oleg Nesterov wrote:
> On 08/10, Serge E. Hallyn wrote:
> > Quoting Pavel Emelyanov (xemul@xxxxxxxxxx):
> > > +/*
> > > + * the namespaces access rules are:
> > > + *
> > > + *  1. only current task is allowed to change tsk->nsproxy pointer or
> > > + *     any pointer on the nsproxy itself
> > > + *
> > > + *  2. when accessing (i.e. reading) current task's namespaces - no
> > > + *     precautions should be taken - just dereference the pointers
> > > + *
> > > + *  3. the access to other task namespaces is performed like this
> > > + *     rcu_read_lock();
> > > + *     nsproxy = task_nsproxy(tsk);
> > > + *     if (nsproxy != NULL) {
> > > + *             / *
> > > + *               * work with the namespaces here
> > > + *               * e.g. get the reference on one of them
> > > + *               * /
> > > + *     } / *
> > > + *         * NULL task_nsproxy() means that this task is
> > > + *         * almost dead (zombie)
> > > + *         * /
> > > + *     rcu_read_unlock();
> > And lastly, I guess that the caller to switch_task_namespaces() has
> > to ensure that new_nsproxy either (1) is the init namespace, (2) is a
> > brand-new namespace to which noone else has a reference, or (3) the
> > caller has to hold a reference to the new_nsproxy across the call to
> > switch_task_namespaces().
> >
> > As it happens the current calls fit (1) or (2).  Again if we happen to
> > jump into the game of switching a task into another task's nsproxy,
> > we'll need to be mindful of (3) so that new_nsproxy can't be tossed into
> > the bin between
> >
> > 	if (new)
> > 		get_nsproxy(new);
>
> 4) Unless tsk == current, get_task_namespaces(tsk) and get_nsproxy(tsk)
>    are racy even if done under rcu_read_lock().

Yup :)

It is already written in comment that only the current is allowed
to change its nsproxy. I.e. when switch_task_nsproxy() is called
for tsk other than current it's a BUG

> Oleg.
>
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