Re: [RFC] div64_64 support

[Jan Engelhardt]

On Feb 26 2007 15:44, Stephen Hemminger wrote:
>> >-		x = (2 * x + (uint32_t) div64_64(a, x*x)) / 3;
>> >+		x = (2 * x + (u32) (a / x*x)) / 3;
>> 
>> Previously there was div64_64(a, x*x) which is equivalent to
>> (a)/(x*x), or just: a/(x^2). But now you do a/x*x, which is
>> equivalent to a*x/x (in the domain of real numbers). Furthermore,
>> a/x*x is a-(a%x), which does not even remotely match a/(x^2).
>> 
>Been there, done that, don't want to repeat it...

I am sorry I don't quite follow.


Jan
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