[PATCH 08/14] uml: fix uname under setarch i386

[Paolo 'Blaisorblade' Giarrusso]

From: Paolo 'Blaisorblade' Giarrusso <blaisorblade@xxxxxxxx>

On a 64bit Uml, if run under "setarch i386" (which a user did), uname()
currently returns the obtained i686 as machine - fix that. Btw, I'm quite
surprised that under setarch i386 a 64-bit binary can run.

Cc: Andi Kleen <ak@xxxxxxx>
Signed-off-by: Paolo 'Blaisorblade' Giarrusso <blaisorblade@xxxxxxxx>
---

 arch/um/os-Linux/util.c |    9 ++++++++-
 1 files changed, 8 insertions(+), 1 deletions(-)

diff --git a/arch/um/os-Linux/util.c b/arch/um/os-Linux/util.c
index 3f5b151..56b8a50 100644
--- a/arch/um/os-Linux/util.c
+++ b/arch/um/os-Linux/util.c
@@ -80,11 +80,18 @@ void setup_machinename(char *machine_out
 	struct utsname host;
 
 	uname(&host);
-#if defined(UML_CONFIG_UML_X86) && !defined(UML_CONFIG_64BIT)
+#ifdef UML_CONFIG_UML_X86
+# ifndef UML_CONFIG_64BIT
 	if (!strcmp(host.machine, "x86_64")) {
 		strcpy(machine_out, "i686");
 		return;
 	}
+# else
+	if (!strcmp(host.machine, "i686")) {
+		strcpy(machine_out, "x86_64");
+		return;
+	}
+# endif
 #endif
 	strcpy(machine_out, host.machine);
 }
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