How to interpret a kernel bug output from dmesg?

[Joshua Hudson]

I got this. Probably I caused it. Kernel is 2.6.13, slightly modified
(weird new psuedo filesystem).
Problem is I don't know how to read it.  I wouldn't recommend looking
for it yourself: I doubt
you will find anything.
Yes, I compiled with DEBUG_DCACHE (or something similar, uncommented the
debug define at the top of dcache.c). I ran dmesg -c just before the ls that
crashed, and dmesg right afterwards. Nothing else present.

------------[ cut here ]------------
kernel BUG at include/linux/dcache.h:294!
invalid operand: 0000 [#1]
PREEMPT
Modules linked in:
CPU:    0
EIP:    0060:[<c0160723>]    Not tainted VLI
EFLAGS: 00010246   (2.6.13c1)
EIP is at __link_path_walk+0xd03/0xe60
eax: 00000000   ebx: ce054014   ecx: 00000001   edx: cdd392fc
esi: ce1b7000   edi: ce1ffecc   ebp: ce1b7f10   esp: ce1b7e24
ds: 007b   es: 007b   ss: 0068
Process ls (pid: 258, threadinfo=ce1b7000 task=ce2eaae0)
Stack: 00000001 ce1b7e50 ce1b7e48 cdd392fc ce1b7e5c ce1b7e54 c02ac704 00000000
       00000000 cfee48c0 ce1ffecc 00017c88 00000002 ce054012 c0169a73 ce1b7f10
       ce1b7f50 ce1b7ebc ce1b7e7c c01608c7 ce00b294 ce054000 ce00b294 cfee48c0
Call Trace:
 [<c0169a73>] dput+0x33/0x280
 [<c01608c7>] link_path_walk+0x47/0xe0
 [<c0160c1c>] path_lookup+0x8c/0x160
 [<c0160eb3>] __user_walk+0x33/0x60
 [<c015ae9c>] vfs_lstat+0x1c/0x60
 [<c015b5cb>] sys_lstat64+0x1b/0x40
 [<c016416d>] sys_fcntl+0x2d/0x60
 [<c0102ab5>] syscall_call+0x7/0xb
Code: 2a ff 02 89 55 00 b8 01 00 00 00 e8 78 de fa ff 8b 46 08 a8 08
75 0d 89 3c 24 e8 29 93 00 00 e9 75 ff ff ff e8 8f 22 11 00 eb ec <0f>
0b 26 01 8e e6 27 c0 eb cc e8 7e 22 11 00 e9 97 fe ff ff 8b
 <6>note: ls[258] exited with preempt_count 1
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