mmap (2) vs read (2)

[Linh Dang]

Hi, how come reading memory from /dev/mem using pread(2) or mmap(2)
will give diffent results?

I run the little prog below 10 times and it always give the following
results

# for i in `seq 1 10`; do ./bar 0x4000000 ; done
04000000: 00000000
pread(04000000): 00cc7d83
04000000: 00000000
pread(04000000): 00cc7d83
04000000: 00000000
pread(04000000): 00cc7d83
04000000: 00000000
pread(04000000): 00cc7d83
04000000: 00000000
pread(04000000): 00cc7d83
04000000: 00000000
pread(04000000): 00cc7d83
04000000: 00000000
pread(04000000): 00cc7d83
04000000: 00000000
pread(04000000): 00cc7d83
04000000: 00000000
pread(04000000): 00cc7d83
04000000: 00000000
pread(04000000): 00cc7d83

thanx


----------------------------------- bar.c ---------------------------------
#include <unistd.h>
#include <stdio.h>
#include <inttypes.h>
#include <sys/types.h>
#include <sys/mman.h>
#include <fcntl.h>
#include <errno.h>


int
main(int argc, char** argv)
{
        uint32_t *addr, item;
        uint32_t offset, val;
        int fd, update = 0;
        if (argc < 2)
                return 1;

        offset  = strtoul(argv[1], NULL, 0);
        if (argc > 2) {
                val = strtoul(argv[2], NULL, 0);
                update = 1;
        } 

        fd   = open("/dev/mem", O_RDWR, 0666);
        addr = mmap(NULL, 4096, PROT_READ|PROT_WRITE, 0x8080|MAP_SHARED, fd, offset);

        if (addr)
        {
                printf("%8.8x: %8.8x", offset, *addr);
                if (update) {
                        *addr = val;
                        msync(addr, 4096, MS_SYNC);
                        printf("-> %8.8x\n", *addr);
                } else
                        printf("\n");

                pread(fd, &item, sizeof(item), offset);
                printf("pread(%8.8x): %8.8x\n", offset, item);

                munmap(addr, 4096);
        }

        close(fd);

}
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