Re: [PATCH] x86 bitops.h commentary on instruction reordering

From: Vladislav Bolkhovitin
Date: Mon Aug 09 2004 - 12:34:12 EST


Marcelo Tosatti wrote:
Not really. x86 doesnt have such an instruction.

But how then spin_lock() works? It guarantees memory sync between CPUs, doesn't it? Otherwise how can it prevent possible races with concurrent data modifications?

It makes use of the "lock" instruction to lock the bus before the "dec" instruction:
#define spin_lock_string \
"\n1:\t" \
"lock ; decb %0\n\t" \
"js 2f\n" \

That way it prevent races wrt other CPUs. atomic accesses which need to modify (atomic_inc, atomic_dec, etc) data also use the "lock" to prevent other CPUs from reading the data.

grep for "lock" in include/asm-i386/.

As hpa said, most x86 instructions (except SSE-related ones) are
strictly ordered (except the cases Alan pointed, which were not known to me).

Thats why there is no "sync"-like instruction on x86 (again, except SSE-related ones).

This is just a simple and short explanation of how this works. It gets more complex
you think about cache coherency between processors, etc. For more details the best book probably is "UNIX Systems for Modern Architectures. Symmetric Multiprocessing and Caching for Kernel Programming" - Curt Schimmel (which has been suggested here over and over).

I know basically, how spinlocks work to provide ordering, my question was about the cache coherency. Thanks for the link to the book, I will try to find it.

Vlad
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