Hi Martin.
> #include <linux/io.h>
> #include <stdio.h>
> #include <stdlib.h>
>
> int main(char *argv[], int argc)
> {
> int port = aoit(argv[0]);
> int byte = aoit(argv[1]);
>
> if (port > 0)
> return inb(port);
> else {
> outb(port, byte);
> return 0;
> }
> }
Interesting code. Did you really mean to have the program name as the
port number, or should that be argv[1] and argv[2] instead? Also, what
is it supposed to do? A quick analysis makes no sense of it.
Would the following be what you had intended?
#include <linux/io.h>
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char **argv) {
int byte, port, result = 0;
switch (argc) {
case 2:
port = atoi(argv[1]);
result = inb(port);
break;
case 3:
port = atoi(argv[1]);
byte = atoi(argv[2]);
outb(port, byte);
break;
default:
fprintf(stderr, "Usage: %s port [byte]\n", argv[0]);
break;
}
return result;
}
Best wishes from Riley.
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This archive was generated by hypermail 2b29 : Fri May 31 2002 - 22:00:18 EST