sendto generates SIGSEGV

From: Oliver Kowalke (oliver.kowalke@t-online.de)
Date: Sun Jul 29 2001 - 14:23:38 EST


Hi,

I've written an c++ class which wrappes a socket.. With function writen()
you can write to an TCP and UDP socket ( TCP : pointer to stuct sockaddr ==
NULL; UDP : pointer to struct sockaddr != NULL). If I use this function
with TCP sockets all works. If I call this function for an UDP socket it
generates an SIGSEGV signal.
What is wrong?

with regards,
Oliver

ssize_t writen( const void * vptr, size_t n, struct sockaddr * to)
{
        size_t nleft = n;
        ssize_t nwritten;
        const char *ptr = static_cast< const char * >( vptr);
        
        struct sigaction new_sa;
        struct sigaction old_sa;
        
        new_sa.sa_handler = SIG_IGN;
        ::sigemptyset( & new_sa.sa_mask);
        new_sa.sa_flags = 0;
        ::sigaction( SIGPIPE, & new_sa, & old_sa);

        while ( nleft > 0)
        {

                if ( ( nwritten = ::sendto( m_handle, ptr, nleft, 0, to,
sizeof * to)

)<=0)
                {
                        if ( errno == EINTR)
                                nwritten = 0; // and call sendto() again
                        else if ( errno == EPIPE)
                        {
                                ::sigaction( SIGPIPE, & old_sa, 0);

                                return -1; // write to sock with
no readers (peer has the sock closed)

                        }
                        else
                        {
                                ::sigaction( SIGPIPE, & old_sa, 0);
                                throw; // error
                        }
                }

                nleft -= nwritten;
                ptr += nwritten;
        }
        ::sigaction( SIGPIPE, & old_sa, 0); // set to its previous action

        return n;
}
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