[PATCH bpf-next v2 6/8] arm32, bpf: add support for 64 bit division instruction

From: Puranjay Mohan
Date: Wed Sep 06 2023 - 14:34:56 EST


ARM32 doesn't have instructions to do 64-bit/64-bit divisions. So, to
implement the following instructions:
BPF_ALU64 | BPF_DIV
BPF_ALU64 | BPF_MOD
BPF_ALU64 | BPF_SDIV
BPF_ALU64 | BPF_SMOD

We implement the above instructions by doing function calls to div64_u64()
and div64_u64_rem() for unsigned division/mod and calls to div64_s64()
for signed division/mod.

Signed-off-by: Puranjay Mohan <puranjay12@xxxxxxxxx>
---
arch/arm/net/bpf_jit_32.c | 119 +++++++++++++++++++++++++++++++++++++-
1 file changed, 118 insertions(+), 1 deletion(-)

diff --git a/arch/arm/net/bpf_jit_32.c b/arch/arm/net/bpf_jit_32.c
index 91b3294963bc..ff4cd749c2f8 100644
--- a/arch/arm/net/bpf_jit_32.c
+++ b/arch/arm/net/bpf_jit_32.c
@@ -2,6 +2,7 @@
/*
* Just-In-Time compiler for eBPF filters on 32bit ARM
*
+ * Copyright (c) 2023 Puranjay Mohan <puranjay12@xxxxxxxxx>
* Copyright (c) 2017 Shubham Bansal <illusionist.neo@xxxxxxxxx>
* Copyright (c) 2011 Mircea Gherzan <mgherzan@xxxxxxxxx>
*/
@@ -15,6 +16,7 @@
#include <linux/string.h>
#include <linux/slab.h>
#include <linux/if_vlan.h>
+#include <linux/math64.h>

#include <asm/cacheflush.h>
#include <asm/hwcap.h>
@@ -238,6 +240,34 @@ static s32 jit_smod32(s32 dividend, s32 divisor)
return dividend % divisor;
}

+/* Wrappers for 64-bit div/mod */
+static u64 jit_udiv64(u64 dividend, u64 divisor)
+{
+ return div64_u64(dividend, divisor);
+}
+
+static u64 jit_mod64(u64 dividend, u64 divisor)
+{
+ u64 rem;
+
+ div64_u64_rem(dividend, divisor, &rem);
+ return rem;
+}
+
+static s64 jit_sdiv64(s64 dividend, s64 divisor)
+{
+ return div64_s64(dividend, divisor);
+}
+
+static s64 jit_smod64(s64 dividend, s64 divisor)
+{
+ u64 q;
+
+ q = div64_s64(dividend, divisor);
+
+ return dividend - q * divisor;
+}
+
static inline void _emit(int cond, u32 inst, struct jit_ctx *ctx)
{
inst |= (cond << 28);
@@ -555,6 +585,81 @@ static inline void emit_udivmod(u8 rd, u8 rm, u8 rn, struct jit_ctx *ctx, u8 op,
emit(ARM_MOV_R(ARM_R0, tmp[1]), ctx);
}

+static inline void emit_udivmod64(const s8 *rd, const s8 *rm, const s8 *rn, struct jit_ctx *ctx,
+ u8 op, u8 sign)
+{
+ u32 dst;
+
+ /* Push caller-saved registers on stack */
+ emit(ARM_PUSH(CALLER_MASK), ctx);
+
+ /*
+ * As we are implementing 64-bit div/mod as function calls, We need to put the dividend in
+ * R0-R1 and the divisor in R2-R3. As we have already pushed these registers on the stack,
+ * we can recover them later after returning from the function call.
+ */
+ if (rm[1] != ARM_R0 || rn[1] != ARM_R2) {
+ /*
+ * Move Rm to {R1, R0} if it is not already there.
+ */
+ if (rm[1] != ARM_R0) {
+ if (rn[1] == ARM_R0)
+ emit(ARM_PUSH(BIT(ARM_R0) | BIT(ARM_R1)), ctx);
+ emit(ARM_MOV_R(ARM_R1, rm[0]), ctx);
+ emit(ARM_MOV_R(ARM_R0, rm[1]), ctx);
+ if (rn[1] == ARM_R0) {
+ emit(ARM_POP(BIT(ARM_R2) | BIT(ARM_R3)), ctx);
+ goto cont;
+ }
+ }
+ /*
+ * Move Rn to {R3, R2} if it is not already there.
+ */
+ if (rn[1] != ARM_R2) {
+ emit(ARM_MOV_R(ARM_R3, rn[0]), ctx);
+ emit(ARM_MOV_R(ARM_R2, rn[1]), ctx);
+ }
+ }
+
+cont:
+
+ /* Call appropriate function */
+ if (sign) {
+ if (op == BPF_DIV)
+ dst = (u32)jit_sdiv64;
+ else
+ dst = (u32)jit_smod64;
+ } else {
+ if (op == BPF_DIV)
+ dst = (u32)jit_udiv64;
+ else
+ dst = (u32)jit_mod64;
+ }
+
+ emit_mov_i(ARM_IP, dst, ctx);
+ emit_blx_r(ARM_IP, ctx);
+
+ /* Save return value */
+ if (rd[1] != ARM_R0) {
+ emit(ARM_MOV_R(rd[0], ARM_R1), ctx);
+ emit(ARM_MOV_R(rd[1], ARM_R0), ctx);
+ }
+
+ /* Recover {R3, R2} and {R1, R0} from stack if they are not Rd */
+ if (rd[1] != ARM_R0 && rd[1] != ARM_R2) {
+ emit(ARM_POP(BIT(ARM_R0) | BIT(ARM_R1)), ctx);
+ emit(ARM_POP(BIT(ARM_R2) | BIT(ARM_R3)), ctx);
+ } else if (rd[1] != ARM_R0) {
+ emit(ARM_POP(BIT(ARM_R0) | BIT(ARM_R1)), ctx);
+ emit(ARM_ADD_I(ARM_SP, ARM_SP, 8), ctx);
+ } else if (rd[1] != ARM_R2) {
+ emit(ARM_ADD_I(ARM_SP, ARM_SP, 8), ctx);
+ emit(ARM_POP(BIT(ARM_R2) | BIT(ARM_R3)), ctx);
+ } else {
+ emit(ARM_ADD_I(ARM_SP, ARM_SP, 16), ctx);
+ }
+}
+
/* Is the translated BPF register on stack? */
static bool is_stacked(s8 reg)
{
@@ -1578,7 +1683,19 @@ static int build_insn(const struct bpf_insn *insn, struct jit_ctx *ctx)
case BPF_ALU64 | BPF_DIV | BPF_X:
case BPF_ALU64 | BPF_MOD | BPF_K:
case BPF_ALU64 | BPF_MOD | BPF_X:
- goto notyet;
+ rd = arm_bpf_get_reg64(dst, tmp2, ctx);
+ switch (BPF_SRC(code)) {
+ case BPF_X:
+ rs = arm_bpf_get_reg64(src, tmp, ctx);
+ break;
+ case BPF_K:
+ rs = tmp;
+ emit_a32_mov_se_i64(is64, rs, imm, ctx);
+ break;
+ }
+ emit_udivmod64(rd, rd, rs, ctx, BPF_OP(code), off);
+ arm_bpf_put_reg64(dst, rd, ctx);
+ break;
/* dst = dst << imm */
/* dst = dst >> imm */
/* dst = dst >> imm (signed) */
--
2.39.2