sched: Am I missing something?
From: Peter Williams
Date: Mon Sep 21 2009 - 09:22:52 EST
Or is the line:
p->prio = effective_prio(p);
in wake_up_new_task() an expensive no op.
As far as I can tell from reading the code, it will always be the case
that EITHER rt_prio(p->prio) is true OR p->prio == p->normal_prio when
this call is made and, in either case, the value of p->prio will be
unchanged. In addition, when this call is made p->normal_prio is
already equal to to normal_prio(p), so the side effects of the function
(setting p->normal_prio) are also unnecessary.
Am I correct or have I missed something?
Peter
--
Peter Williams pwil3058@xxxxxxxxxxxxxx
"Learning, n. The kind of ignorance distinguishing the studious."
-- Ambrose Bierce
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